How do you find f(g(5)) given $f (x) = 4 x + 3$ $f(x)=4x+3$ and $g (x) = x - 2$ $g(x)=x-2$ ?

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How do you find f(g(5)) given $f (x) = 4 x + 3$ $f(x)=4x+3$ and $g (x) = x - 2$ $g(x)=x-2$ ?

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Answer 1 · 2016-10-16T15:46:46

$f (g (5)) = 15$ $f(g(5))=15$

Explanation:

$f (x) = 4 x + 3$ $f(x)=4x+3$
$g (x) = x - 2$ $g(x)=x-2$
$f (g (x)) = f (x - 2) = 4 (x - 2) + 3 = 4 x - 8 + 3 = 4 x - 5$ $f(g(x))=f(x-2)=4(x-2)+3=4x-8+3=4x-5$
$f (g (5)) = 4 \cdot 5 - 5 = 20 - 5 = 15$ $f(g(5))=4*5-5=20-5=15$

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How do you find f(g(5)) given $f (x) = 4 x + 3$ $f(x)=4x+3$ and $g (x) = x - 2$ $g(x)=x-2$ ?

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How do you find f(g(5)) given f(x)=4x+3f(x)=4x+3f(x)=4x+3 and g(x)=x-2g(x)=x−2g(x)=x-2?

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How do you find f(g(5)) given $f (x) = 4 x + 3$ $f(x)=4x+3$ and $g (x) = x - 2$ $g(x)=x-2$ ?