How do you find f'(1) if $f(x)= x^2*tan^-1 x$ ?

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Answer 1 · 2015-05-18T16:57:23

It would be $pi/2+1/2$

f' (x)= $2x tan^-1 x + x^2 /(1+x^2)$

f' (1)= $2tan^-1 1+ 1/2$

= $2pi/4 +1/2$

= $pi/2 +1/2$

How do you find f'(1) if f(x)= x^2*tan^-1 xf(x)= x^2*tan^-1 x?