How do you find exact value of $csc (-7pi/ 3)$ ?

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Answer 1 · 2016-09-22T14:54:20

$csc(-(7pi)/3)=-2/sqrt3=-1.155$

All trigonometric functions have a cycle of $2pi$

Hence $csc(-(7pi)/3)$

= $csc(-(7pi)/3+2pi)$

= $csc(-(7pi)/3+(6pi)/3)$

= $csc(-pi/3)=-csc(pi/3)$

= $-2/sqrt3$

= $-(2xxsqrt3)/(sqrt3xxsqrt3)$

= $(-2xx1.732)/3=-3.464/3=-1.155$

How do you find exact value of csc (-7pi/ 3)csc (-7pi/ 3)?