How do you find equations of the lines passing through (1,3 ) passing through point (2,4)?

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Answer 1 · 2016-07-28T17:40:40

#x-y+2=0#

Equation of a line joining two points #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#

Hence equation of line joining #(1,3)# and #(2,4)# is

#(y-3)/(4-3)=(x-1)/2-1)# or

#(y-3)/1=(x-1)/1# or

#y-3=x-1# i.e.

#x-y+2=0#