How do you find domain and range for #y=sqrt(x- 2)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Konstantinos Michailidis Oct 7, 2015 The domain is #x>=2# or #D(f)=[2,+oo)# and the range is #y=sqrt(x-2)>=0=>y>=0# or #R(f)=[0,+oo)# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1724 views around the world You can reuse this answer Creative Commons License