How do you find domain and range for $f(x) = (x-6)/(x+1)$ ?

Question

2832 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-30T04:51:01

Below

$f(x)=(x-6)/(x+1)$

$f(x)=((x+1)-7)/(x+1)$

$f(x)=1-7/(x+1)$

Therefore, the domain is all reals except when $x=-1$ and range is all reals except when $y=1$

How do you find domain and range for f(x) = (x-6)/(x+1)f(x) = (x-6)/(x+1)?