How do you find domain and range for $f(x) = sqrt(7x + 2)$ ?

Question

5118 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-28T16:12:57

The domain is $x in [-2/7, +oo)$ . The range is $y in [0,+oo)$

Let $y=sqrt(7x+2)$

What's under the square root sign is $>=0$

Therefore,

$7x+2>=0$

$=>$ , $x>=-2/7$

The domain is $x in [-2/7, +oo)$

When,

$x=-2/7$ , $=>$ , $y=0$

And

$lim_(x->+oo)sqrt(7x+2)=+oo$

Therefore,

The range is $y in [0,+oo)$

graph{sqrt(7x+2) [-7.06, 21.42, -7.46, 6.78]}

How do you find domain and range for f(x) = sqrt(7x + 2) f(x) = sqrt(7x + 2)?