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How do you find angle A in the following triangle, length of a = 17cm angle c = 105, Length of C = 37cm?

1 Answer

Mar 7, 2017

${26.35}^{\circ}$ $26.35^@$

Explanation:

Using the $sine rule$ $color(blue)"sine rule"$ in the triangle.

$color(red)(bar(ul(|color(white)(2/2)color(black)(a/sinA=c/sinC)color(white)(2/2)|)))$

$rArr(17)/sinA=37/sin105^@$

$color(blue)"cross-multiply"$

$rArr37sinA=17sin105^@$

$rArrsinA=(17sin105^@)/37$

$rArrA=sin^-1((17sin105^@)/37)$

$rArr"angle A "≈26.35^@" to 2 decimal places"$

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