How do you find all zeros of the function $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{3}$ $f(x) = 4(x + 7)^2(x - 7)^3$ ?

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How do you find all zeros of the function $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{3}$ $f(x) = 4(x + 7)^2(x - 7)^3$ ?

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Answer 1 · 2016-09-26T16:46:17

Zeros of $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{2}$ $f(x)=4(x+7)^2(x-7)^2$ are $- 7$ $-7$ and $7$ $7$ .

Explanation:

If $f (x) = u {(x - a)}^{m} {(x - b)}^{n} {(x - c)}^{p} {(x - d)}^{q}$ $f(x)=u(x-a)^m(x-b)^n(x-c)^p(x-d)^q$ , a multiplication of number of binomials of degree one, then zeros of polynomials are $a$ $a$ , $b$ $b$ , $c$ $c$ and $d$ $d$ , as any of them when put in place of $x$ $x$ will make $f (x) = 0$ $f(x)=0$ . Here $u$ $u$ is just a constant.

Hence, zeros of $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{2}$ $f(x)=4(x+7)^2(x-7)^2$ are $- 7$ $-7$ and $7$ $7$ .

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How do you find all zeros of the function $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{3}$ $f(x) = 4(x + 7)^2(x - 7)^3$ ?

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Explanation:

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How do you find all zeros of the function f(x) = 4(x + 7)^2(x - 7)^3f(x)=4(x+7)2(x−7)3 f(x) = 4(x + 7)^2(x - 7)^3?

1 Answer

Explanation:

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How do you find all zeros of the function $f (x) = 4 {(x + 7)}^{2} {(x - 7)}^{3}$ $f(x) = 4(x + 7)^2(x - 7)^3$ ?