How do you find all zeros of the function $f(x) = 4(x + 7)^2(x - 7)^3$ ?

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How do you find all zeros of the function $f(x) = 4(x + 7)^2(x - 7)^3$ ?

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Answer 1 · 2016-09-26T16:46:17

Zeros of $f(x)=4(x+7)^2(x-7)^2$ are $-7$ and $7$ .

Explanation:

If $f(x)=u(x-a)^m(x-b)^n(x-c)^p(x-d)^q$ , a multiplication of number of binomials of degree one, then zeros of polynomials are $a$ , $b$ , $c$ and $d$ , as any of them when put in place of $x$ will make $f(x)=0$ . Here $u$ is just a constant.

Hence, zeros of $f(x)=4(x+7)^2(x-7)^2$ are $-7$ and $7$ .

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How do you find all zeros of the function $f(x) = 4(x + 7)^2(x - 7)^3$ ?

1 Answer

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Science

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How do you find all zeros of the function f(x) = 4(x + 7)^2(x - 7)^3 f(x) = 4(x + 7)^2(x - 7)^3?

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Explanation:

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How do you find all zeros of the function $f(x) = 4(x + 7)^2(x - 7)^3$ ?