How do you find all the zeros of $f(x) = x^4+ -7x^2 -144$ ?

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Answer 1 · 2016-03-11T02:47:39

$x = +-4, +-3i$

$f(x) - x^4 - 7x^2 - 144$ (Since $"+ -" = -$ )

Let $z = x^2$
$f(x) = z^2 - 7z - 144$

To find all zeros set $f(x) = 0$
$z^2 - 7z - 144 = 0$

Factorizing:
$(z+9) (z-16) = 0$

Therefore $z = -9 or 16$

But $z = x^2 -> x = +- sqrt(z)$

With $z = -9, x = +-3i$
And with $z = 16, x = +-4$

How do you find all the zeros of f(x) = x^4+ -7x^2 -144f(x) = x^4+ -7x^2 -144?