How do you find all the zeros of #f(x)=x^4-5x^2-36#?
1 Answer
Aug 14, 2016
Explanation:
Note that
So we find:
#x^4-5x^2-36#
#=(x^2-9)(x^2+4)#
#=(x^2-3^2)(x^2-(2i)^2)#
#=(x-3)(x+3)(x-2i)(x+2i)#
Hence zeros:
