How do you find all the zeros of #f(x)=x^4-5x^2-36#?

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How do you find all the zeros of #f(x)=x^4-5x^2-36#?

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Answer 1 · 2016-03-10T21:43:19

#x={-3,-2,2,3}#

Explanation:

let #u=x^2# then #f(x)=x^4-5x^2-36 ->f(u)=u^2-5u-36#
#u^2-5u-36=0#
#(u-9)(u+4)=0#
#u-9=0,u+4=0#
#u=9 or u=-4#
#x^2=9,x^2=4#
#x=+-3,x=+-2#
#x={-3,-2,2,3}#

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How do you find all the zeros of #f(x)=x^4-5x^2-36#?

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