How do you find all six trigonometric functions of $(5pi)/6$ ?

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Answer 1 · 2015-05-22T03:48:44

On the trig unit circle:

$sin ((5pi)/6) = sin (pi - pi/6) = sin (pi/6) = 1/2$

$cos ((5pi)/6) = cos (pi - pi/6) = -cos (pi/6) = (-sqrt3)/2$

$tan ((5pi)/6) = 1/(-sqrt3) = (-sqrt3)/3$

$cot ((5pi)/6) = 1/tan ((5pi)/6)$ =

$sec = 1/cos ((5pi)/6)$

$csc = 1/sin ((5pi)/6) =$

How do you find all six trigonometric functions of (5pi)/6(5pi)/6?