How do you find #abs(-5 + 0i)#?
1 Answer
May 27, 2018
Explanation:
#"given a complex number "x+yi" then"#
#"the magnitude of the number is"#
#•color(white)(x)|x+yi|=sqrt(x^2+y^2)#
#|-5+0i|=sqrt(5^2+0^2)=sqrt25=5#