How do you find a vector perpendicular to the vectors v=(1 3 -2) and u=(1 2 -2)?

Question

2513 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-17T09:11:12

The Reqd. Vector $=(-2,0,-1)$ .

It is known from the Vector Geometry that the Cross Product

or Vector Product of given two vectors $vecx$ and $vecy$ ,

denoted by $vecx xx vecy$ is a vector $bot$ to both $vecx$ and

$vecy$ .

Hence, the Reqd. Vector $=vec v xx vec u$

$=det|(hati,hatj,hatk),(1,3,-2),(1,2,-2)|$

$=(-6+4)hati-(-2+2)hatj+(2-3)hatk$

$=-2hati-hatk$

$=(-2,0,-1)$ .