How do you find a standard form equation for the line with points (-6, 1) and (-5, 2)?

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How do you find a standard form equation for the line with points (-6, 1) and (-5, 2)?

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Answer 1 · 2016-06-09T06:14:05

$y = x + 7$ $y=x+7$

Explanation:

Given -

$x_{1} = - 6$ $x_1=-6$
$y_{1} = 1$ $y_1=1$
$x_{2} = - 5$ $x_2=-5$
$y_{2} = 2$ $y_2=2$

$y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)$

$y - 1 = \frac{2 - 1}{(- 5) - (- 6)} (x - (- 6))$ $y-1=(2-1)/((-5)-(-6))(x-(-6))$
$y - 1 = \frac{1}{- 5 + 6} (x + 6)$ $y-1=1/(-5+6)(x+6)$
$y - 1 = \frac{1}{1} (x + 6)$ $y-1=1/1(x+6)$
$y = x + 6 + 1$ $y=x+6+1$
$y = x + 7$ $y=x+7$

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How do you find a standard form equation for the line with points (-6, 1) and (-5, 2)?

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