How do you find a standard form equation for the line with points (-6, 1) and (-5, 2)?
1 Answer
Jun 9, 2016
y=x+7
Explanation:
Given -
x_1=-6
y_1=1
x_2=-5
y_2=2
y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)
y-1=(2-1)/((-5)-(-6))(x-(-6))
y-1=1/(-5+6)(x+6)
y-1=1/1(x+6)
y=x+6+1
y=x+7
