How do you find a standard form equation for the line (0,2) (1,-2)?

1 Answer
Josephine J.
Jan 9, 2018

4x + y = 2

Explanation:

Your first step in this process is to find the slope.
#(y_"2"-y_"1")/(x_"2"-x_"1")# = #(-2-2)/(1-0)#

This gives you a slope of #-4/1#

Your second step is to plug it into the point slope form with one of the points you were given.
#(y-y_"1")=m(x-x_"1")# = #(y-2)=-4/1(x-0)#

Your third step is to simplify that into your standard form which is #Ax+Bx=C#
#1(y-2) = 1[ -4(x-0)]#
#y-2=-4x+0# Distribute
#y-2+4x=0# Move the #x# value to the other side with inverse operations.
#y+4x=2# Move the #C# value to the other side with inverse operations.
#4x+y=2# Rearrange accordingly to get into the #Ax + By=C# formula.

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