How do you find a power series converging to f(x)=cossqrtx and determine the radius of convergence?

1 Answer
Aug 7, 2017

f(x) = 1-(x)/(2!) + (x^2)/(4!) - (x^3)/(6!) + ...

This converges AA x in RR

Explanation:

First let us consider the well known Maclaurin series for cos x. We could derive this from first principles, but is is rarely required to do this and is quoted on most examination formula books:

cos x = 1-(x^2)/(2!) + (x^4)/(4!) - (x^6)/(6!) + ...

And this series converges AA x in RR

So, now replace x by sqrt(x) and we get:

f(x) = cos sqrt(x)
" " = cos(x^(1/2))
" " = 1-((x^(1/2))^2)/(2!) + ((x^(1/2))^4)/(4!) - ((x^(1/2))^6)/(6!) + ...
" " = 1-(x)/(2!) + (x^2)/(4!) - (x^3)/(6!) + ...

Again, this converges AA x in RR