How do you find a polynomial function with zeroes 3,-2,1?

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How do you find a polynomial function with zeroes 3,-2,1?

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Answer 1 · 2015-10-20T09:01:53

The polynomial is: #x^3-2x^2-5x+6#

Explanation:

When a number #a# is a zero of a polynomial, then this polynomial is divisible by #(x-a)#, so to find the polynomial with zeros #-2,1,3# you have to multiply #(x+2)(x-1)(x-3)#

#(x+2)(x-1)(x-3)=(x^2+x-2)*(x-3)=x^3+x^2-2x-3x^2-3x+6=x^3-2x^2-5x+6#

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How do you find a polynomial function with zeroes 3,-2,1?

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