How do you find a=6b+4c given b=<6,3> and c=<-4,8>?

1 Answer
Jim G.
Aug 28, 2017

a=((20),(50))

Explanation:

a=6((6),(3))+4((-4),(8))

"multiply each component in the vector by the scalar"

a=((36),(18))+((-16),(32))

"add/subtract corresponding x/y components"

a=((20),(50))

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