How do you find a=1/3(2b-5c) given b=<6,3> and c=<-4,8>?

1 Answer
Jim G.
Aug 21, 2017

ula=((32/3),(-34/3))

Explanation:

ula=1/3(2ulb-5ulc)

color(white)(xx)=1/3[2((6),(3))-5((-4),(8))]

"multiply each component by the scalar quantity"

ula=1/3[((12),(6))+((20),(-40))]

"add corresponding components in each vector"

rArrula=1/3((32),(-34))=((32/3),(-34/3))

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