How do you find 2 positive consecutive odd integers whose product is 483?
1 Answer
Jan 23, 2016
21 and 23
Explanation:
let n be an odd integer.
Then the next consecutive odd number will be n + 2. Odd
integers are separated by 2 ( 1 , 3 , 5 ,7 , 9......)
The product of n and n+ 2 = n(n + 2 ) =483
(distribute the brackets )
hence :
n2+2n−483=0 To factor require 2 numbers that multiply to give - 483 and sum
to give +2. These are 23 and - 21 .
check : 23 # xx ( - 21 ) = - 483 and 23 - 21 = 2
so (n + 23 )( n - 21 ) = 0
⇒n=−23orn=21 Now n ≠ - 23 so n = 21 and n + 2 = 21 + 2 = 23
