How do you factor #y=x^3 + 6x^2 - 4x - 24 # ?

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Answer 1 · 2015-12-16T06:27:16

#y=(x+6)(x-2)(x+2)#

#y=x^3+6x^2-4x-24# => factor by grouping:
#y=x^2(x+6)-4(x+6)#
#y=(x +6)(x^2-4)# => use difference of squares:
#y=(x+6)(x-2)(x+2)#

Answer 2 · 2015-12-16T06:29:33

#y=(x+2)(x-2)(x+6)#

#y=x^3+6x^2-4x-24#

#y=x^2(x+6)-4(x+6)#

#y=(x^2-4)(x+6)#

#y=(x+2)(x-2)(x+6)#