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How do you factor: #y= n^2-7n+12 #?

1 Answer

Dec 22, 2015

#y=(n-3)(n-4)#

Explanation:

#y=n^2-7n+12#

#Delta=1#
For #y=0#, #n_1=(7-sqrtDelta)/2, n_2=(7+sqrtDelta)/2#

Therefore,
#y=(n-3)(n-4)#

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