How do you factor: #y=3x^3 - 8x^2 - x + 10#?

1 Answer
Nghi N.
Mar 31, 2016

We find that y(2) = 0 when x = 2, then one factor is (x - 2).
After division and checking,
#y = (x - 2)(3x^2 - 2x - 5).#
The trinomial in parentheses can be factored.
Since (a - b + c = 0), use shortcut. One factor is (x + 1) and the other is #(x - 5/3)#
Finally,
#y = (x - 2)(x + 1)(x - 5/3)#

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