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How do you factor #y^2 + 0.2y - 0.15#?

1 Answer

Aug 28, 2016

#y^2+0.2y-0.15=(y+0.5)(y-0.3)#

Explanation:

Note that #5*3 = 15# and #5-3 = 2#. We use this later...

If we let #x=0.1# then:

#y^2+0.2y-0.15#

#=y^2+2xy-15x^2#

#=(y+5x)(y-3x)#

#=(y+0.5)(y-0.3)#

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