How do you factor #xy³ - 49xyz²#?

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How do you factor #xy³ - 49xyz²#?

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Answer 1 · 2015-05-29T15:24:29

Both terms have #x# and #y# as common factors, so #xy^3-49xyz^2=xy(y^2-49z^2)#. But #y^2-49z^2# is the difference of two squares. The final answer is:

#xy^3-49xyz^2=xy(y-7z)(y+7z)#

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How do you factor #xy³ - 49xyz²#?

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