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How do you factor $(x^8)-16$ ?

1 Answer

Konstantinos Michailidis

Nov 4, 2015

It is

$x^8-16=(x^4)^2-4^2=(x^4-4)*(x^4+4)=(x^2-2)*(x^2+2)*[(x^2+2)^2-4x^2]=(x^2-2)*(x^2+2)*(x^2+2-2x)*(x^2+2+2x)$

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