How do you factor #x^6 + 2x^3y^2 + y^4#?
1 Answer
Jan 3, 2016
#x^6+2x^3y^2+y^4 = (x^3+y^2)^2#
Explanation:
We can recognise this as a perfect square trinomial, since it is of the form
#x^6+2x^3y^2+y^4#
#=(x^3)^2 + 2(x^3)(y^2) + (y^2)^2#
#=(x^3+y^2)^2#
