How do you factor #x^4 -3x^2 -4= 0#?

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How do you factor #x^4 -3x^2 -4= 0#?

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Answer 1 · 2016-05-19T04:58:13

#(x^2 + 1)(x - 2)(x + 2)#

Explanation:

Call #x^2 = X#, the trinomial transforms itself to -->
#y = X^2 - 3X - 4.#
Since a - b + c = 0, use shortcut.
The 2 factors are: (X + 1) and# (X + c/a = X - 4).#
#y = (X + 1)(X - 4) = (x^2 + 1)(x^2 - 4) = #
#= (x^2 + 1)(x - 2)(x + 2)#

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How do you factor #x^4 -3x^2 -4= 0#?

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