How do you factor #x^4-2x^3-12x^2+18x+27#?

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How do you factor #x^4-2x^3-12x^2+18x+27#?

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Answer 1 · 2015-05-07T16:46:19

Answer #(x+1)(x-3)^2(x+3)#

Try #x=-1# gives #1+2-12-18+27=0# so #x+1# is a factor.
Dividing by #(x+1)# gives #x^3-3x^2-9x+27#
Try #x=3# in cubic gives #27-27-27+27=0# so #x-3# is a factor
Dividing by #(x-3)# gives #x^2-9# which factors to #(x-3)(x+3)#

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How do you factor #x^4-2x^3-12x^2+18x+27#?

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