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How do you factor #x^3y^2-xy^4#?

1 Answer

Jul 12, 2015

I found: #xy^2(x-y)(x+y)#

Explanation:

you can collect #xy^2# and remember that #a^2-b^2=(a+b)(a-b)# to get:
#xy^2(x^2-y^2)=xy^2(x-y)(x+y)#

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