How do you factor #x(3x - yz) + 2yz(3x - yz)#?
1 Answer
Feb 13, 2016
(3x - yz)(x + 2yz )
Explanation:
in the expression
# x(3x - yz ) + 2yz(3x - yz )# there is a 'common factor' of (3x - yz )
removing this leaves x in the 1st term and +2yz in the 2nd.
hence factors are : (3x - yz )(x + 2yz )
