How do you factor #x^3+8y^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Bill Jorgensen Jun 9, 2018 #(x + 2y)(x^2 – 2xy + 4y^2)# Explanation: This is a difference of cubes so use the formula: #a^3 + b^3 = (a + b)(a^2 – ab + b^2)# #x^3 + 8y^3 = (x + 2y)(x^2 – x2y + 2^2y^2)# #= (x + 2y)(x^2 – 2xy + 4y^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5851 views around the world You can reuse this answer Creative Commons License