How do you factor #x^3+6x^2-x-30#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Cem Sentin Mar 14, 2018 #(x-2)(x+3)(x+5)# Explanation: #x^3+6x^2-x-30# =#x^3-8+6x^2-24-(x-2)# =#(x-2)(x^2+2x+4)+6(x+2)(x-2)-(x-2)# =#(x-2)*[(x^2+2x+4)+6(x+2)-1]# =#(x-2)*(x^2+8x+15)# =#(x-2)(x+3)(x+5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 11669 views around the world You can reuse this answer Creative Commons License