How do you factor #x^3 + 6x^2 + 12x + 8#?

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Answer 1 · 2016-08-25T19:16:21

#(x+2)^3#.

The Expression#=x^3+6x^2+12x+8#

#=(x^3+8)+6x(x+2)#

#=ul((x+2))(x^2-2x+4)+6xul((x+2)#

#=(x+2){x^2-2x+4+6x}#

#=(x+2)(x^2+4x+4)#

#=(x+2){x^2+2(2)(x)+2^2}#

#=(x+2)(x+2)^2#

#=(x+2)^3#.