How do you factor $x^3+27=0$ ?

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Answer 1 · 2017-02-18T17:17:32

$(x+3)(x^2-3x+9)=0$

We have a standard polynomial on LHS of the form $a^3+b^3$ , whose one factor is $(a+b)$ . So one factor is $(x+3)$

$x^3+27=0$

$hArrx^3+3x^2-3x^2-9x+9x+27=0$

or $x^2(x+3)-3x(x+3)+9(x+3)=0$

or $(x+3)(x^2-3x+9)=0$

How do you factor x^3+27=0x^3+27=0?