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How do you factor #x^3+27=0#?

1 Answer

Shwetank Mauria

Feb 18, 2017

#(x+3)(x^2-3x+9)=0#

Explanation:

We have a standard polynomial on LHS of the form #a^3+b^3#, whose one factor is #(a+b)#. So one factor is #(x+3)#

#x^3+27=0#

#hArrx^3+3x^2-3x^2-9x+9x+27=0#

or #x^2(x+3)-3x(x+3)+9(x+3)=0#

or #(x+3)(x^2-3x+9)=0#

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