How do you factor $x²-2x-8$ ?

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Answer 1 · 2018-05-03T23:27:26

$(x-4)(x+2)$

$x^2 - 2x - 8$

To factor something, we should first make sure that it is in the form of $ax^2 + bx + c$ to make it easier, which this expression is in.

Then, we have to find two numbers that:

Those two numbers are $-4$ and $2$ :

Now we put them into factored form, which is: $(x-4)(x+2)$ .

Hope this helps!

How do you factor x²-2x-8x²-2x-8?