How do you factor #x^2 - 4x - 12#?
1 Answer
Mar 4, 2018
Explanation:
#"consider the factors of - 12 which sum to - 4"#
#"these are - 6 and + 2"#
#rArrx^2-4x-12=(x-6)(x+2)#
#"consider the factors of - 12 which sum to - 4"#
#"these are - 6 and + 2"#
#rArrx^2-4x-12=(x-6)(x+2)#