How do you factor $x^2 + 33x - 108$ ?

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Answer 1 · 2018-03-03T21:07:13

$x^2+33x-108 = (x+36)(x-3)$

Find a pair of factors of $108$ which differ by $33$ .

The pair $36, 3$ works in that $36 * 3 = 108$ and $36 - 3 = 33$

Hence:

$x^2+33x-108 = (x+36)(x-3)$

How do you factor x^2 + 33x - 108x^2 + 33x - 108?