How do you factor $x^{2} - 28 x + 196$ $x^2-28x+196$ ?

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How do you factor $x^{2} - 28 x + 196$ $x^2-28x+196$ ?

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Answer 1 · 2017-08-31T10:57:05

${(x - 14)}^{2}$ $(x-14)^2$

Explanation:

$note that - 14 \times - 14 = 196 and -14 +(-14)=-28$ $"note that "-14xx-14=196" and -14 +(-14)=-28"$

$\Rightarrow x^{2} - 28 x + 196$ $rArrx^2-28x+196$

$= (x - 14) (x - 14)$ $=(x-14)(x-14)$

$= {(x - 14)}^{2}$ $=(x-14)^2$

Answer 2 · 2017-08-31T11:06:20

$(x - 14) (x - 14)$ $(x - 14) (x - 14)$

Explanation:

$x^{2} - 28 x + 196$ $x^2 - 28x + 196$

This is a quadratic equation, hence there are 2 factors..

When finding factors, you need to have two numbers, that will multiply themselves to give the constant and then add or subtract themselves to give the coefficient of $x$ $x$ ..

What am referring to is $- 28 x$ $-28x$ and $+ 196$ $+196$

Hence we have $14$ $14$ as the factor;

$\to + 196 = - 14 \times - 14$ $-> +196 = - 14 xx - 14$

$\to - 28 x = - 14 x + (- 14 x)$ $-> -28x = - 14x + (- 14x)$

Hence Imputing in the main equation we have..

$x^{2} - 28 x + 196$ $x^2 - 28x + 196$

$x^{2} - 14 x - 14 x + 196$ $x^2 - 14x - 14x + 196$

$(x^{2} - 14 x) (- 14 x + 196)$ $(x^2 - 14x) (-14x + 196)$

Extract the common factor!

$x (x - 14) - 14 (x - 14)$ $color(blue)x(x - 14) color(blue)(- 14)(x - 14)$

Separating the factors!

$(x - 14) (x - 14)$ $(x - 14) color(blue)((x - 14)$

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How do you factor $x^{2} - 28 x + 196$ $x^2-28x+196$ ?

2 Answers

Explanation:

Explanation:

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How do you factor $x^{2} - 28 x + 196$ $x^2-28x+196$ ?