How do you factor $x^{2} - 25$ $x^2-25$ ?

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Answer 1 · 2015-05-02T08:44:09

The answer is $(x + 5) (x - 5)$ $(x+5)(x-5)$ .

$(x^{2} - 25)$ $(x^2-25)$ fits the pattern of the difference of squares in which $(a^{2} - b^{2}) = (a + b) (a - b)$ $(a^2-b^2)=(a+b)(a-b)$ .

The factorization of $(x^{2} - 25) = (x^{2} - 5^{2})$ $(x^2-25)=(x^2-5^2)$ =

$(x + 5) (x - 5)$ $(x+5)(x-5)$

How do you factor x2−25x^2-25?