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How do you factor #x^2+18x+81#?

1 Answer

Shwetank Mauria

Jun 1, 2016

#x^2+18x+81=(x+9)^2#

Explanation:

As #81# is the square of #9# and middle term #18# is double of this number, (compare it with #(x+a)^2=x^2+2ax+a^2#)

Hence #x^2+18x+81# is a complete square.

#x^2+18x+81#

= #x^2+2xx9xx x+9^2#

= #(x+9)^2#

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