How do you factor $x^{2} + 10 x + 3$ $x^2+10x+3$ ?

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Answer 1 · 2015-05-22T15:06:49

You can find its roots and then turn them into factors.

Let's use Bhaskara.

$\frac{- 10 \pm \sqrt{100 - 4 (1) (3)}}{2}$ $(-10+-sqrt(100-4(1)(3)))/2$

$x_{1} = - 5 - \sqrt{22}$ $x_1=-5-sqrt(22)$
$x_{2} = - 5 + \sqrt{22}$ $x_2=-5+sqrt(22)$

So, equaling them to zero will give you the factors:

$(x + 5 + \sqrt{22}) (x + 5 - \sqrt{22})$ $(x+5+sqrt(22))(x+5-sqrt(22))$

How do you factor x2+10x+3x^2+10x+3?