How do you factor $w^3-27$ ?

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Answer 1 · 2016-02-28T07:03:56

$w^3-27=(w-3)(w^2+3w+9)$

Use the formula for "difference of 2 cubes"

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Let $a=w$ and $b=3$
because $a^3=w^3$ and $b^3=3^3=27$

then

$w^3-27=(w-3)(w^2+3w+9)$

God bless....I hope the explanation is useful..

How do you factor w^3-27w^3-27?