How do you factor the trinomial #x^2-11x+18#?

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How do you factor the trinomial #x^2-11x+18#?

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Answer 1 · 2016-01-03T01:58:06

Find two numbers that posses the product of the c term (last term, without a variable) and the sum of the b term (the middle term, with an x coefficient, degree one)

Explanation:

#x^2# - 11x + 18 ---> -9 - 2 = -11 and -9 • -2 = 18
= (x - 9)(x - 2)

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How do you factor the trinomial #x^2-11x+18#?

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