How do you factor the trinomial #6d^2+21d= 10d+35 #?

1 Answer
Roella W.
Nov 19, 2015

Rearrange all the factors to be on one side of the expression and then factorize as normal

Explanation:

#6d^2 +21d - 10d -35 = 0#
#6d^2 +11d -35 = 0#
35 is #7*5# and 6 is #3*2#
By studying the numbers 11 can be obtained from 21 (#7*3#) minus 10 (#5*2#)
#(3d - 5)(2d + 7) = 0#
#d = 5/3# or #d = -7/2#

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
1854 views around the world
You can reuse this answer
Creative Commons License