How do you factor the trinomial #4x^2 - 9x - 9#?

1 Answer
Shantelle
Apr 4, 2018

Here's what I did:

Explanation:

#4x^2-9x-9#

To factor this, we need to find 2 numbers which:

  • multiply up to #-36#
  • add up to #-9#

These 2 numbers are #-12# and #3#. So now the expression looks like this:
#4x^2 - 12x + 3x - 9#

Now we can factor by grouping:
#4x(x-3) + 3(x-3)#

And the final factored format is:
#(4x+3)(x-3)#

Hope this helps!

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