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How do you factor the trinomial # 49 - 4x^2#?

1 Answer

Nov 23, 2015

#7^2-(2x)^2=(7+2x)(7-2x)#

Explanation:

#49-4x^2# represents a difference of squares, in which #a^2-b^2=(a+b)(a-b)#, where #a=7 and b=2x#.

#7^2-(2x)^2=(7+2x)(7-2x)#

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