How do you factor the trinomial #2x^2 - 32x + 128#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Nghi N. Dec 2, 2015 Factor #2x^2 - 32x + 128# Explanation: #y = 2x^2 - 32x + 128 = 2(x^2 - 16x + 64) = 2(x - 6)^2# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 4388 views around the world You can reuse this answer Creative Commons License